If it's not what You are looking for type in the equation solver your own equation and let us solve it.
7x^2+23x-12=0
a = 7; b = 23; c = -12;
Δ = b2-4ac
Δ = 232-4·7·(-12)
Δ = 865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{865}}{2*7}=\frac{-23-\sqrt{865}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{865}}{2*7}=\frac{-23+\sqrt{865}}{14} $
| y-39=-27 | | a+19=53 | | n-36=-42 | | 0.02*x=12 | | -9x-9=4x=39 | | 2x-8=10x-20 | | 2x-8=10x+20 | | X-0.7x=20 | | 3x=5x-1=23 | | 2x-88=126 | | x+1/2x+1/7x+2/3x=33 | | -3x^+8x-7=0 | | y=-0.89+241.7 | | 2x/(x^2+x)=2 | | 2^x*2^x+1=8 | | x6-9=4x | | F(x)=2/3x+6 | | 8-7x=4+5x | | X=3+x/1+4x | | 99/x=496 | | ¾x-6=3 | | 4k+7(-4-2k)=-2(k+2) | | 1+6x=-11+4x | | 8^(x^2)=7^x | | 9+4c=-15 | | 2x+1+13=90 | | 30=14-(x-4) | | 4y-1+2y=9 | | 19x=360 | | -9=-6v+3(v+6) | | |2x+9|=|X+12|= | | |-6x-5|=|-3x+6| |